Calculate the energy (in kW⋅h)given off if five kg of plutonium-239 undergoes complete fission.The energy released per fission is 200 MeV.(1 MeV = 1.6 × 10−¹³ J) A)1.1E+11 kW⋅h B)6.4E+12 kW⋅h C)1.6E+16 kW⋅h D)1.1E+8 kW⋅h E)5.4E+9 kW⋅h

Question

Quizplus · Accepted Answer

First, calculate the number of atoms in 5 kg of Pu-239 using Avogadro's number. Then, multiply by the energy per fission (200 MeV converted to joules) to find the total energy in joules. Finally, convert joules to kW⋅h.

Calculate the Energy (In KW⋅h)given Off If Five Kg of Plutonium-239