What is the surface area,approximately,of a Lead-208 nucleus (Z = 82)?

Name: What is the surface area,approximately,of a Lead-208 nucleus (Z = 82)?
Brand: Quizplus
Rating: 4.9 (47 reviews)

Question

Quizplus · Accepted Answer

The surface area of a nucleus is given by 4πr^2, where r is the radius of the nucleus. The radius of a nucleus is given by r = r0A^(1/3), where r0 is a constant and A is the mass number of the nucleus. For Lead-208, A = 208, so r = 1.2A^(1/3) fm = 1.2(208)^(1/3) fm = 6.6 fm. Therefore, the surface area of a Lead-208 nucleus is 4π(6.6 fm)^2 = 550 fm^2.

What Is the Surface Area,approximately,of a Lead-208 Nucleus (Z =