The work function of a certain material is 4.9 eV.What is the photoelectric minimum (threshold)frequency for this material? A)1.18 * 10¹⁵ Hz B)2.23 * 10¹⁵ Hz C)9.01 * 10¹⁴ Hz D)3.48 * 10¹⁵ Hz E)2.56 * 10¹⁵ Hz

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Quizplus · Accepted Answer

The minimum (threshold) frequency ($f_0$) for the photoelectric effect can be calculated using the equation $E = hf_0$, where $E$ is the work function in joules, $h$ is Planck's constant ($6.626 \times 10^{-34}$ J·s), and $f_0$ is the threshold frequency in Hz. First, convert the work function from eV to joules (1 eV = $1.602 \times 10^{-19}$ J), so $4.9 \, \text{eV} = 4.9 \times 1.602 \times 10^{-19} \, \text{J}$. Then, solve for $f_0$: $f_0 = \frac{E}{h}$. Substituting the given values and solving for $f_0$ yields a value in the range of $1.18 \times 10^{15}$ Hz, which corresponds to choice A.

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