A helium-neon laser puts out a beam of red light with frequency 4.74 * 10¹⁴ Hz.Determine the energy of each photon at that frequency. A)1.96 eV B)2.50 eV C)8.81 eV D)13.6 eV E)25.0 eV

Question

Quizplus · Accepted Answer

The energy of each photon is given by E = hf, where h is Planck's constant (6.626 x 10^-34 J.s) and f is the frequency of the light. 
Substituting the given values, we get:
E = (6.626 x 10^-34 J.s)(4.74 x 10^14 Hz) = 1.96 eV. 
Therefore, the correct answer is A) 1.96 eV.

A Helium-Neon Laser Puts Out a Beam of Red Light