Light of wavelength 450 nm is incident on two slits in a piece of paper separated by 1 mm.What is the angle of the twelfth interference maximum?

Question

Quizplus · Accepted Answer

The formula for the angle of the nth interference maximum is given by:

θn = nλ/d

where λ is the wavelength of the light, d is the separation between the slits and n is the order of the interference maximum.

For the twelfth interference maximum, n = 12, λ = 450 nm and d = 1 mm = 10^-3 m.

Plugging these values into the formula, we get:

θ12 = 12(450 nm) / (10^-3 m) = 5.4 mrad

Therefore, the angle of the twelfth interference maximum is 5.4 mrad. Hence, the correct answer is C.

Light of Wavelength 450 Nm Is Incident on Two Slits