X-rays of wavelength 0.14 nm are directed toward a crystal.The first order diffraction peak appears at 11 $\circ$ for certain crystallographic planes.The separation between the planes is

Question

Quizplus · Accepted Answer

The Bragg's Law equation for diffraction is given by:

nλ = 2d sinθ

Where n is the order of the diffraction peak, λ is the wavelength of the incident X-ray, d is the distance between the crystal planes, and θ is the angle of incidence.

In this problem, we are given:

n = 1 (first order diffraction peak)
λ = 0.14 nm
θ = 11°

Solving for d, we get:

d = nλ/(2sinθ) = (1)(0.14 nm)/(2sin11°) ≈ 0.367 nm

Therefore, the separation between the planes is 0.367 nm, which corresponds to choice C.

X-Rays of Wavelength 0 ∘\circ∘ for Certain Crystallographic Planes

X-Rays of Wavelength 0 $\circ$ for Certain Crystallographic Planes