X-rays of wavelength 1.25 angstroms are incident upon a crystal face in a Bragg refraction experiment.If the first order peak is observed at 17.0 $\circ$ relative to the crystal surface,what is the crystal spacing being probed?

Question

Quizplus · Accepted Answer

Using Bragg's Law, $ n\lambda = 2d\sin\theta $, where $ n = 1 $, $\lambda = 1.25 $ angstroms, and $\theta = 17.0^\circ$, we solve for $ d $: $ d = \frac{1 \times 1.25}{2 \sin(17.0^\circ)} \approx 2.14 $ angstroms.

X-Rays of Wavelength 1 ∘\circ∘ Relative to the Crystal Surface,what Is the Crystal Spacing

X-Rays of Wavelength 1 $\circ$ Relative to the Crystal Surface,what Is the Crystal Spacing