You have single slit diffraction with a wavelength of 570 nm at a distance of 100 cm.If the distance to the third minimum from the center of the pattern is 0.85 mm,what is the width of the slit?

Question

Quizplus · Accepted Answer

We can use the formula for the distance to the nth minimum in single slit diffraction: 
d*sin(theta) = n*wavelength 
where d is the width of the slit, theta is the angle from the central maximum to the nth minimum, and n is the order of the minimum. 
In this case, n = 3 and theta can be approximated as sin(theta) = 0.85 mm / 100 cm = 0.0085. 
Solving for d, we get: 
d = (n*wavelength) / sin(theta) = (3*570 nm) / 0.0085 = 2000 nm = 2.0 mm. 
Therefore, the width of the slit is 2.0 mm, or choice D.

You Have Single Slit Diffraction with a Wavelength of 570