A concave mirror has a radius of curvature of 30 cm.An object is located 45 cm in front of the mirror.Where is the image formed,and what are its properties?

Question

Quizplus · Accepted Answer

Using the mirror equation $ \frac{1}{f} = \frac{1}{v} + \frac{1}{u} $, where $ f $ is the focal length, $ v $ is the image distance, and $ u $ is the object distance. Given the radius of curvature is 30 cm, the focal length $ f = \frac{R}{2} = 15 $ cm. The object distance $ u = -45 $ cm (negative because it's in front of the mirror). Plugging these values into the mirror equation gives $ \frac{1}{15} = \frac{1}{v} - \frac{1}{45} $, solving for $ v $ gives $ v = 22.5 $ cm, indicating the image is formed 22.5 cm in front of the mirror. Since it's a concave mirror and the object is outside the focal length, the image is real and inverted.

A Concave Mirror Has a Radius of Curvature of 30