Unpolarized light of intensity 100 mW/m² passes through two filters.The first filter has an alignment of 30.0 degrees from the vertical.The intensity of the light that passes through the second filter is 41 mW/m².What is the angular alignment of the second filter with respect to the vertical?

Question

Quizplus · Accepted Answer

The intensity of the light that passes through the second filter is given by:$$I = I_0 \cos^2 	heta$$where:* I is the intensity of the light that passes through the second filter* I_0 is the intensity of the light that passes through the first filter* θ is the angle between the alignment of the second filter and the alignment of the first filterWe know that I = 41 mW/m^2 and I_0 = 100 mW/m^2. Therefore, we can solve for θ:$$\cos^2 	heta = \frac{I}{I_0} = \frac{41 mW/m^2}{100 mW/m^2} = 0.41$$$$	heta = \cos^{-1} \sqrt{0.41} = 5 degrees$$

Unpolarized Light of Intensity 100 MW/m2 Passes Through Two Filters

Unpolarized Light of Intensity 100 MW/m² Passes Through Two Filters