An ideal transformer contains a primary coil of 200 turns and a secondary coil of 120 turns.The secondary coil drives a current I through an R = 1-k$\varOmega$ resistor.If an input V_rms = 75 V is applied across the primary coil,how much power is dissipated in the resistor,R? A)4 W B)0.5 W C)1 W D)2 W

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Quizplus · Accepted Answer

The power dissipated in the resistor is calculated using the formula P = V^2/R. The voltage across the secondary coil is V_secondary = (N_secondary/N_primary) * V_primary = (120/200) * 75 V = 45 V. Therefore, the power dissipated is P = (45^2)/1000 = 2.025 W, approximately 2 W.

An Ideal Transformer Contains a Primary Coil of 200 Turns Ω\varOmegaΩ

An Ideal Transformer Contains a Primary Coil of 200 Turns $\varOmega$