An inductor of inductance L and a resistor of resistance R are connected in series.This series combination is then connected across the terminals of a battery.After a very long time,the battery is suddenly removed from the circuit and the circuit is made to form a closed loop so that the current continues to flow.How long after the battery is removed is the current flowing through the resistor equal to half its value before the battery was removed?
A) t = L/2R
B) t = L/R
C) t = 2L/R
D) None are correct.
Correct Answer:
Verified
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