A long,straight wire is located along the x-axis (y = 0 and z = 0).The wire carries a current of 5.0 A in the +x direction.What is the magnitude of the force on a 2.0 C charged particle located at (+2.0 m,+1.0 m,0),when it has a velocity of 300 m/s in the +z-direction? A)0.0 N B)1.5 * 10^-4 N C)2.7 * 10^-4 N D)3.0 * 10^-4 N E)6.0 * 10^-4 N

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Quizplus · Accepted Answer

The force on a charged particle moving in a magnetic field is given by the Lorentz force equation, $F = q(\vec{v} \times \vec{B})$, where $q$ is the charge, $\vec{v}$ is the velocity of the particle, and $\vec{B}$ is the magnetic field. Since the particle is moving in the +z direction and the current is in the +x direction, the magnetic field at the location of the particle due to the current in the wire would be in the plane perpendicular to the direction of the current (in this case, in the y-z plane). However, since the particle's velocity is parallel to the direction of the magnetic field lines (both in the z direction), the cross product $\vec{v} \times \vec{B}$ is zero, resulting in a force of 0.0 N.

A Long,straight Wire Is Located Along the X-Axis (Y =