A straight wire of length 3.5 m carries a current of 42 A and it is placed on a horizontal table in a horizontal uniform magnetic field of 0.14 T.If the wire makes an angle of 44 $\circ$ with the magnetic field lines,what is the magnitude of the magnetic force on the wire?

Question

Quizplus · Accepted Answer

The magnetic force on a current-carrying wire is given by F = I * L * B * sin(θ), where I is the current, L is the length of the wire, B is the magnetic field, and θ is the angle between the wire and the magnetic field. Substituting the given values: F = 42 A * 3.5 m * 0.14 T * sin(44°) ≈ 14 N.

A Straight Wire of Length 3 ∘\circ∘ with the Magnetic Field Lines,what Is the Magnitude of of 42

A Straight Wire of Length 3 $\circ$ with the Magnetic Field Lines,what Is the Magnitude of of 42