A straight wire of length 3.5 m carries a current of 42 A and it is placed on a horizontal table in a horizontal uniform magnetic field of 0.14 T.If the magnitude of the magnetic force on the wire is 9.0 N,what is the angle the between the wire and the magnetic field lines?

Question

Quizplus · Accepted Answer

The magnetic force on a current carrying wire in a uniform magnetic field is given by F = BILsinθ, where B is the magnetic field strength, I is the current, L is the length of the wire and θ is the angle between the wire and the magnetic field lines.

Plugging in the given values, we get:

9.0 N = (0.14 T) x (42 A) x (3.5 m) x sinθ

Solving for sinθ, we get:

sinθ = 9.0 N / (0.14 T x 42 A x 3.5 m)

θ = sin-1 (0.253)

θ ≈ 26°

Therefore, the angle between the wire and the magnetic field lines is approximately 26°. The answer is choice C.

A Straight Wire of Length 3 ∘\circ∘ B)44 ∘\circ∘ C)26 ∘\circ∘

A Straight Wire of Length 3 $\circ$
B)44^$\circ$
C)26^$\circ$