The Hall affect is used to measure the carrier density of a thin sheet of electrons.When a current of 80.0 $\mu$A flows through the length of the electron sheet,which is 1.2-mm long and 0.27-mm wide,a magnetic field of 0.75 T perpendicular to the sheet produces a potential difference of 0.53 mV across the width of the sheet.If the carrier density in the electron sheet is 6.74 * 10²⁵ m^-3,what is the thickness of the sheet?

Question

Quizplus · Accepted Answer

The thickness of the sheet can be calculated using the Hall effect formula, which relates the Hall voltage (V_H), magnetic field (B), current (I), charge carrier density (n), and the thickness of the sheet (d). The formula is V_H = (B * I) / (n * e * d), where e is the charge of an electron. Rearranging the formula to solve for d gives d = (B * I) / (V_H * n * e). Substituting the given values and solving for d yields a thickness close to 10 nm.

The Hall Affect Is Used to Measure the Carrier Density μ\muμ

The Hall Affect Is Used to Measure the Carrier Density $\mu$