A proton with an initial velocity of (1.0x + 2.0y + 3.0z)* 10⁵ m/s enters a magnetic field of 0.50z T.Find the magnitude of the force on the proton.The mass of the proton is 1.67 *10^-27 kg.Where x,y and z are unit vectors in the x,y and z directions,respectively.

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The force on a charged particle in a magnetic field is given by F = q(v × B). The charge of a proton is approximately 1.6 × 10^-19 C. The velocity vector is (1.0x + 2.0y + 3.0z) × 10^5 m/s and the magnetic field is 0.50z T. The cross product v × B results in a vector perpendicular to both v and B. Calculating the cross product and then the magnitude of the force gives approximately 1.8 × 10^-14 N.

A Proton with an Initial Velocity of (1