In the circuit shown,determine the charge on each capacitor when switch S has been closed for a long time,where R₁ = 1 k$\varOmega$,R₂ = 2 k$\varOmega$,C₁ = 1 $\mu$F,and C₂ = 2 $\mu$F. A)Q₁ = 3.33 µC and Q₂ = 6.66 µC B)Q₁ = 3.33 µC and Q₂ = 13.3 µC C)Q₁ = 13.3 µC and Q₂ = 3.33 µC D)Q₁ = 6.66 µC and Q₂ = 13.3 µC

Question

Quizplus · Accepted Answer

Since the capacitors are in series, the charges on them will be equal. Let Q be the charge on each capacitor. Using the formula for capacitors in series, we have: 1/Ceq = 1/C₁ + 1/C₂ = 1/1 + 1/2 = 3/2 Ceq = 2/3 µF The total voltage across the capacitors is 10 V, so we have: Q = Ceq * V = (2/3) * 10 = 6.66 µC for each capacitor. Therefore, the correct answer is B.

In the Circuit Shown,determine the Charge on Each Capacitor When Ω\varOmegaΩ

In the Circuit Shown,determine the Charge on Each Capacitor When $\varOmega$