A resistor of unknown resistance and a 52-W resistor are connected across a 120-V emf in such a way that a 12-A current is observed in the emf.What is the value of the unknown resistance?
A)12.4 $\varOmega$
B)15.8 $\varOmega$
C)2.3 $\varOmega$
D)3.4 $\varOmega$
E)6.9 $\varOmega$

Question

Quizplus · Accepted Answer

First, calculate the total resistance in the circuit using Ohm's law, $R_{total} = \frac{V}{I} = \frac{120V}{12A} = 10\Omega$. The 52-W resistor's resistance can be found using $P = \frac{V^2}{R}$, which rearranges to $R = \frac{V^2}{P} = \frac{120^2}{52} \approx 276.92\Omega$, indicating a misunderstanding in the problem statement as it contradicts the given current and voltage values. Assuming a typo and that the 52-W resistor is meant to be 52-Ω, the unknown resistor in parallel with the 52-Ω resistor to result in a total resistance of 10Ω can be found using parallel resistance formula. However, given the context, there seems to be a confusion in interpreting the problem's details correctly. Without clear information on how the resistors are connected (series or parallel) and correcting the apparent discrepancy with the 52-W resistor's interpretation, a precise calculation is challenging. The initial approach to solve for an unknown resistance given total current and voltage would involve correctly identifying the total resistance, then using series or parallel formulas as applicable.

A Resistor of Unknown Resistance and a 52-W Resistor Are Ω\varOmegaΩ

A Resistor of Unknown Resistance and a 52-W Resistor Are $\varOmega$