What is the resistance of a 15.0-m long,24-gauge (0.511 mm diameter)copper wire? The resistivity of copper is 1.72 * 10^-8 $\varOmega$m.

Question

Quizplus · Accepted Answer

We can use the formula for the resistance of a wire: R = (ρL)/A, where ρ is the resistivity of copper, L is the length of the wire, and A is the cross-sectional area of the wire. First, we need to find the cross-sectional area of the 24-gauge wire, which can be calculated from the diameter as A = πr^2 = π(0.511/2)^2 = 0.205 mm^2 = 2.05 x 10^-7 m^2. Plugging in the values, we get R = (1.72 x 10^-8)(15.0)/2.05 x 10^-7 = 1.26 Ω. Therefore, the answer is B.

What Is the Resistance of a 15 Ω\varOmegaΩ M A)0315 Ω\varOmegaΩ B)126 Ω\varOmegaΩ

What Is the Resistance of a 15 $\varOmega$ M
A)0315 $\varOmega$ B)126 $\varOmega$