A 100-W light bulb is connected to a 120-V DC power outlet.If the wires leading to that power outlet have a resistance of 1.2 ohms,how much power is wasted in the connecting wires?

Question

Quizplus · Accepted Answer

The power wasted in the wires can be calculated using the formula $P = I^2R$, where $I$ is the current and $R$ is the resistance. First, find the current using the power of the bulb and the voltage: $P = IV$, so $I = P/V = 100W / 120V = 0.833A$. Then, calculate the power wasted: $P = I^2R = (0.833A)^2 \times 1.2\Omega = 0.83W$.

A 100-W Light Bulb Is Connected to a 120-V DC