A battery has an internal resistance of 1.3 $\varOmega$ and a voltage of 48.0 V.Is a load of 15.0 $\varOmega$ is connected to the battery,what is the voltage across the terminals of the battery?

Question

Quizplus · Accepted Answer

We can use Ohm's Law, combined with the concept of voltage drop across internal resistance, to solve for the voltage across the battery terminals.

The current flowing through the circuit is:

I = V / R_total

where R_total = R_load + R_internal

Plugging in the given values, we get:

I = 48.0 V / (15.0 Ω + 1.3 Ω) = 3.478 A

The voltage drop across the internal resistance is:

V_internal = I * R_internal = 3.478 A * 1.3 Ω = 4.52 V

Therefore, the voltage across the battery terminals is:

V_battery = V_load + V_internal = 48.0 V - 4.52 V = 43.48 V

Rounding to the nearest tenth, we get:

V_battery ≈ 44.2 V

So, the correct answer is B.

A Battery Has an Internal Resistance of 1 Ω\varOmegaΩ And a Voltage of 48

A Battery Has an Internal Resistance of 1 $\varOmega$ And a Voltage of 48