The resistivity of gold at room temperature is 2.35 * 10^-8 $\varOmega$ *m.The temperature coefficient $\alpha$ = 3.98 * 10^-3/K.What will be the resistivity of a piece of gold whose temperature is 150 $\circ$ C above room temperature?

Question

Quizplus · Accepted Answer

The resistivity at a higher temperature can be calculated using the formula: $\rho = \rho_0 (1 + \alpha \Delta T)$. Here, $\rho_0 = 2.35 \times 10^{-8} \, \Omega \cdot m$, $\alpha = 3.98 \times 10^{-3}/K$, and $\Delta T = 150 \, K$. Substituting these values gives $\rho = 2.35 \times 10^{-8} \times (1 + 3.98 \times 10^{-3} \times 150) = 3.75 \times 10^{-8} \, \Omega \cdot m$.

The Resistivity of Gold at Room Temperature Is 2 Ω\varOmegaΩ *MThe Temperature Coefficient

The Resistivity of Gold at Room Temperature Is 2 $\varOmega$ *MThe Temperature Coefficient