A parallel plate capacitor has square plates of side L = 12 cm,and a distance d = 2 cm between the plates.Half of the capacitor area is filled with a dielectric of with k₁= 35.The other half is filled with a different dielectric with k₂ = 8.The effective (equivalent)capacitance of the capacitor is

Question

Quizplus · Accepted Answer

The capacitance can be calculated using the formula:

C = (k1*k2/(k1+k2))*(epsilon0*A/d)

where k1 and k2 are the dielectric constants of the two regions, A is the area of each plate, d is the distance between the plates, and epsilon0 is the permittivity of free space.

For the first region, k1 = 35 and the area is 1/2 of total area, so:

C1 = (35*1)/(35+1)*epsilon0*(1/2*L)^2/d

For the second region, k2 = 8 and the area is also 1/2 of total area, so:

C2 = (8*1)/(8+1)*epsilon0*(1/2*L)^2/d

Thus, the total capacitance is:

C = C1 + C2 = (35*8)/(35+8)*epsilon0*(1/2*L)^2/d = 1.4 F

A Parallel Plate Capacitor Has Square Plates of Side L