Two parallel plates are held at a potential of + 220 V and + 130 V.If the plates have area of 44 cm² and are separated by a distance of 7.3 mm,what is the magnitude of the electric field between the plates?

Question

Quizplus · Accepted Answer

The electric field (E) between two parallel plates is given by the formula E = V/d, where V is the potential difference between the plates and d is the separation distance. The potential difference V = 220V - 130V = 90V. The distance d = 7.3 mm = 0.0073 m. Thus, E = 90V / 0.0073m = 12,328.77 N/C, which is approximately 12,000 N/C.

Two Parallel Plates Are Held at a Potential of