What is the electric field 0.25 m away from a -6.5 $\mu$C point charge?

Question

Quizplus · Accepted Answer

The electric field created by a point charge is given by:
E = kQ/r^2
where k = 9 x 10^9 Nm^2/C^2 is the Coulomb constant, Q is the charge in coulombs, and r is the distance between the point charge and the point where we want to calculate the electric field in meters.

In this case, Q = -6.5 x 10^-6 C and r = 0.25 m. Therefore:

E = (9 x 10^9 Nm^2/C^2)(-6.5 x 10^-6 C)/(0.25 m)^2 
E = -9.4 x 10^6 N/C

The negative sign indicates that the electric field is directed towards the point charge. Therefore, the correct answer is C) 9.4 x 10^6 N/C towards the point charge (rounded to one significant figure, the answer is 6.1 N/C).

What Is the Electric Field 0 μ\muμ C Point Charge? A)6

What Is the Electric Field 0 $\mu$ C Point Charge?
A)6