A cubical box has six faces,each 20 cm * 20 cm.The flux through each face is (the sides are labeled like a die,sides 1 and 6 are opposite to each other,as are 2 and 5,and 3 and 4. Side Flux (Nm²/C)
1 -120
2 + 300
3 -100
4 + 600
5 -40
6 -150
Find the net charge inside the cube.

Question

Quizplus · Accepted Answer

Using Gauss's Law, we can find the net charge inside the cube by finding the total flux through the surfaces of the cube and dividing by the electric constant.

The total flux through each face is given in the problem, so we can just add them up:

Total flux = (-120 Nm + 300 Nm - 100 Nm + 600 Nm - 40 Nm - 150 Nm) = 490 Nm

Dividing by the electric constant (8.85 x 10^-12 C^2/Nm^2), we get:

Net charge = (490 Nm) / (8.85 x 10^-12 C^2/Nm^2) = 4.3 x 10^-10 C

Therefore, the best choice is D: 4.3 x 10^-10 C.

A Cubical Box Has Six Faces,each 20 Cm * 20