In the figure the net electrostatic force on charge Q_A is zero.If Q_A = +1 nC,determine the magnitude of Q₀ if position of Q_A is (+2a,-2a). A)4.24 nC B)3.04 nC C)6.80 nC D)9.61 nC E)2.15 nC

Question

Quizplus · Accepted Answer

Since the net electrostatic force on Q_A is zero, the magnitudes of the electrostatic forces due to Q and S at Q_A must be equal and opposite, i.e., we can write: k(Q₀)(1 nC)(1 nC) / [(2a)^2 + (2a)^2] = k(1 nC)x / [(2a)^2 + (2a)^2] Simplifying and solving for x, we get: x = 3.04 nC Therefore, the magnitude of Q₀ is 3.04 nC.

In the Figure the Net Electrostatic Force on Charge QA

In the Figure the Net Electrostatic Force on Charge Q_A