In Bohr's model of the hydrogen atom an electron revolves in a circular orbit of radius 0.053 nm around a proton.The number of revolutions made by the electron in one second is A)12.8 * 10³⁹. B)9.8 * 10³⁵. C)4.3 * 10³¹. D)6.6 * 10¹⁵. E)6.2 * 10¹².

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Quizplus · Accepted Answer

The frequency of revolution of the electron is given by the formula f = v/2πr, where v is the velocity of the electron and r is the radius of the circular orbit. Using the formula for the centripetal force F=mv²/r and Coulomb's law, we can find the velocity of the electron, which is given by v = (1/4πε₀)(ke²/mr), where ε₀ is the permittivity of free space, e is the charge on an electron, k is Coulomb's constant, m is the mass of the electron, and r is the radius of the circular orbit. Substituting the given values, we get v = 2.19 x 10⁶ m/s. Therefore, the frequency of revolution is f = (2.19 x 10⁶)/(2π x 0.053 x 10⁻⁹) = 6.6 x 10¹⁵ Hz, which is option D.

In Bohr's Model of the Hydrogen Atom an Electron Revolves