The diameter of C¹² nucleus is 2.75 * 10^-15 m.It has a charge of +6e.The magnitude of the force on a proton placed 2 * 10^-15 m from its surface is A)121.4 N. B)345.6 N. C)542.1 N. D)632.5 N. E)980.1 N.

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The force can be calculated using Coulomb's law, $F = \frac{k \cdot q_1 \cdot q_2}{r^2}$, where $k$ is Coulomb's constant ($8.987 \times 10^9 \, \text{N m}^2/\text{C}^2$), $q_1$ and $q_2$ are the charges of the two objects, and $r$ is the distance between them. The charge of the nucleus is +6e (where $e = 1.602 \times 10^{-19} \, \text{C}$), and the charge of a proton is also $e$. The distance $r$ is the sum of the radius of the nucleus and the distance from its surface, which is $2.75 \times 10^{-15} \, \text{m} + 2 \times 10^{-15} \, \text{m} = 4.75 \times 10^{-15} \, \text{m}$. Substituting these values into Coulomb's law gives the force.

The Diameter of C12 Nucleus Is 2

The Diameter of C¹² Nucleus Is 2