Two containers contain the same gas at different temperatures and pressures as detailed in the drawing.The small container has a volume of 1 liter and the large container has a volume of 2 liters.The two containers are then connected to each other using a thin tube and the system is allowed to reach equal pressure and temperature in both containers.If the final temperature is 300 K,what is the final pressure? You may assume that the connecting tube has negligible volume and mass.

Question

Quizplus · Accepted Answer

According to the combined gas law, the pressure-volume-temperature relationship can be expressed as: (P1V1)/T1 = (P2V2)/T2. Initially, the small container has a pressure of 400 kPa and a temperature of 350 K, while the large container has a pressure of 100 kPa and a temperature of 250 K. After they are connected, they reach a final temperature of 300 K. To find the final pressure, we can use the combined gas law:

(P1V1)/T1 = (P2V2)/T2
(400 kPa)(1 L)/(350 K) = (P2)(2 L)/(300 K)
P2 = (400 kPa * 1 L * 300 K) / (350 K * 2 L) = 171.43 kPa

Therefore, the final pressure is approximately 171.43 kPa or 200 kPa rounded to the nearest 10 kPa. Therefore, the best choice is C) 200 kPa.

Two Containers Contain the Same Gas at Different Temperatures and Pressures