One hundred grams of liquid argon is sealed inside of a 2.0 liter container.After the liquid argon turns into a gas and the gas reaches a temperature of 0.0 degrees Celsius,what is the pressure inside the container due to the liquid argon?

Question

Quizplus · Accepted Answer

The pressure can be calculated using the ideal gas law, PV = nRT. First, convert 100 grams of argon to moles (100 g / 39.95 g/mol ≈ 2.5 mol). Use R = 0.0821 L·atm/mol·K and T = 273 K. Solving for P gives P = (2.5 mol * 0.0821 L·atm/mol·K * 273 K) / 2.0 L ≈ 28 atm.

One Hundred Grams of Liquid Argon Is Sealed Inside of a 2.0