The temperature of an ideal gas is doubled (in K)and its volume is decreased to 25% of its original value.How is the pressure affected?

Question

Quizplus · Accepted Answer

The pressure of an ideal gas is directly proportional to its temperature (in Kelvin) and inversely proportional to its volume. If the temperature is doubled and the volume is decreased to 25% (or 1/4) of its original value, the pressure would increase by a factor of 2 (due to temperature doubling) and by a factor of 4 (due to volume reduction to 1/4), resulting in an overall increase by a factor of 8. Therefore, P' = 8P.

The Temperature of an Ideal Gas Is Doubled (In K)and