How many joules of energy need to be added to a 1-cm³ block of lead to increase its temperature from room temperature (20 $\circ$ C)to 37 $\circ$ C?

Question

Quizplus · Accepted Answer

To calculate the energy needed to change the temperature of a substance, you can use the formula $Q = mc\Delta T$, where $Q$ is the heat energy in joules, $m$ is the mass in kilograms, $c$ is the specific heat capacity (for lead, it's approximately 128 J/kg°C), and $\Delta T$ is the change in temperature in degrees Celsius.Given:- The mass of the lead block is 1 cm³. The density of lead is approximately 11.34 g/cm³, so the mass is 11.34 g or 0.01134 kg.- The change in temperature ($\Delta T$) is from 20°C to 37°C, so $\Delta T = 37°C - 20°C = 17°C$.Plugging these values into the formula:$Q = 0.01134 \, \text{kg} \times 128 \, \text{J/kg°C} \times 17 \, \text{°C} = 24.6 \, \text{J}$Rounding to the nearest whole number gives approximately 25 J.

How Many Joules of Energy Need to Be Added to a 1-Cm3

How Many Joules of Energy Need to Be Added to a 1-Cm³