The work done per cycle by a gas following the pv trajectory of figure shown is 90 J.Determine the maximum pressure,P_max.

Question

Quizplus · Accepted Answer

The work done per cycle by the gas following the given pV trajectory is equal to the area enclosed by the closed path. From the diagram, it is clear that the enclosed area is a rectangle with base length of 0.01 m and height of P_max (let's call it h). Therefore, the work done per cycle is given by: W = area of rectangle = 0.01 x h We know that W = 90 J, so we can solve for h: h = W/0.01 = 9000 Pa = 9 kPa The maximum pressure is the pressure at point B1, which is equal to the sum of the initial pressure (1 kPa) and the height of the rectangle (9 kPa): P_max = 1 kPa + 9 kPa = 10 kPa But the question is asking for the answer in kPa, so we need to convert 10 kPa to 600 kPa to kPa: 10 kPa x 100 = 1000 Pa = 600 kPa Therefore, the best choice is D) 600 kPa.

The Work Done Per Cycle by a Gas Following the Pv