A piece of metal 0.12 m² in cross sectional area is cooled by 30 $\circ$ C and is stretched by a force of 95 * 10⁵ N.If the fractional change in length is 1.12 * 10^-3,what is Young's modulus for the metal? ($\alpha$ = 19 * 10^-6 C^-1)

Question

Quizplus · Accepted Answer

Young's modulus (Y) is calculated using the formula Y = (F/A) / (ΔL/L), where F is the force applied, A is the cross-sectional area, ΔL/L is the fractional change in length. Given F = 95 x 10^5 N, A = 0.12 m^2, and ΔL/L = 1.12 x 10^-3, substituting these values gives Y = (95 x 10^5 N / 0.12 m^2) / (1.12 x 10^-3) = 4.7 x 10^10 N/m^2.

A Piece of Metal 0 ∘\circ∘ C and Is Stretched by a Force of 95

A Piece of Metal 0 $\circ$ C and Is Stretched by a Force of 95