What is the sound intensity 2.65 m away from a 125 W speaker that is emitting sound uniformly in all directions?

Question

Quizplus · Accepted Answer

The formula for sound intensity at a certain distance from a point source is:

I = P/4πr^2

where P is the power emitted by the source and r is the distance from the source.

In this case, P = 125 W and r = 2.65 m. Plugging in these values, we get:

I = 125/(4π(2.65)^2) = 0.424 W/m^2

To convert this value to decibels (dB), we use the formula:

dB = 10 log(I/I0)

where I0 is the reference intensity of 10^-12 W/m^2.

Plugging in the values, we get:

dB = 10 log(0.424/10^-12) = 122 dB

Therefore, the answer is C: 122 dB.

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