A pendulum on a distant planet oscillates 20 times in 10.0 seconds.The length of the pendulum is 25.0 cm.What is the acceleration due to gravity on this planet? Ignore friction and air resistance. A)2.00 m/s² B)9.81 m/s² C)39.5 m/s² D)200 m/s²

Question

Quizplus · Accepted Answer

We can use the formula for the period of a simple pendulum:

T = 2π√(L/g)

where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.

Rearranging the formula, we get:

g = (4π^2L) / T^2

Substituting the given values, we get:

g = (4π^2(0.25)) / (10^2) = 39.5 m/s^2

Therefore, the acceleration due to gravity on this planet is 39.5 m/s^2, which corresponds to choice C.

A Pendulum on a Distant Planet Oscillates 20 Times in 10.0