What is the frequency of a 1.30-m long simple pendulum in an elevator that is moving upward with a uniform acceleration of 1.20 m/s²? A)0.437 Hz B)0.463 Hz C)1.35 Hz D)2.91 Hz E)18.3 Hz

Question

Quizplus · Accepted Answer

The frequency of a simple pendulum is given by the formula: f = 1/(2π) √(g/l), where g is the acceleration due to gravity and l is the length of the pendulum. 
In this case, since the elevator is moving upward with a uniform acceleration of 1.20 m/s^2, the effective acceleration experienced by the pendulum will be g + a = 9.81 + 1.20 = 11.01 m/s^2. 
Substituting this value along with the given length of 1.30 m into the formula, we get: 
f = 1/(2π) √(11.01/1.30) ≈ 0.463 Hz 
Therefore, the best choice is B, 0.463 Hz.

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