Osteoporosis is a disease occurring especially in women after menopause in which the bones become very porous and as a result break easily with a fall or the application of even a small amount of force.Assume the breaking stress of a bone is 1.30 * 10⁷ N/m²,the magnitude of the maximum force a disease femur bone 3-cm in average diameter could withstand is

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The breaking stress ($\sigma$) of a bone is given as $1.30 \times 10^7 \, \text{N/m}^2$. The cross-sectional area ($A$) of a femur bone with an average diameter ($d$) of 3 cm (or 0.03 m) can be calculated using the area formula for a circle, $A = \pi r^2$, where $r$ is the radius of the bone. Since the diameter is 3 cm, the radius is 1.5 cm or 0.015 m. Thus, $A = \pi (0.015)^2 \, \text{m}^2$.The maximum force ($F$) that the bone can withstand without breaking can be calculated using the formula $F = \sigma A$.Substituting the given values:$$F = 1.30 \times 10^7 \, \text{N/m}^2 \times \pi (0.015)^2 \, \text{m}^2$$$$F \approx 9.19 \, \text{kN}$$Therefore, the magnitude of the maximum force a diseased femur bone can withstand is approximately 9.19 kN.

Osteoporosis Is a Disease Occurring Especially in Women After Menopause