A piece of aluminum is 13 cm long and when subject to a compressional force of 540 N,compresses by 0.13 mm.What is its area in mm²? Young's modulus for Aluminum is 7.0 * 10¹⁰ Pa. A)7.7 B)4.3 * 10³ C)0.123 D)0.95 E)1.6 * 10^-6

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Quizplus · Accepted Answer

The area can be calculated using the formula for Young's modulus, $Y = \frac{F \cdot L}{A \cdot \Delta L}$, where $F$ is the force applied, $L$ is the original length, $A$ is the cross-sectional area, and $\Delta L$ is the change in length. Rearranging for $A$, we get $A = \frac{F \cdot L}{Y \cdot \Delta L}$. Substituting the given values ($F = 540\,N$, $L = 13\,cm = 130\,mm$, $\Delta L = 0.13\,mm$, $Y = 7.0 \times 10^{10}\,Pa$), we find $A = \frac{540 \cdot 130}{7.0 \times 10^{10} \cdot 0.13} = 7.7\,mm^2$.

A Piece of Aluminum Is 13 Cm Long and When