A 3.3-m long wire with a cross sectional area of 4.7 * 10^-5 m² is stretched 8.3 * 10^-4 m by a force of 234 N.What is Young's modulus for this material? A)1.98 * 10¹⁰ N/m² B)5.67 * 10¹² N/m² C)9.81 * 10⁸ N/m² D)4.55 * 10⁶ N/m² E)3.21 * 10^-11 N/m²

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Quizplus · Accepted Answer

Young's modulus (Y) is calculated using the formula Y = (F/A) / (ΔL/L), where F is the force applied, A is the cross-sectional area, ΔL is the change in length, and L is the original length. Substituting the given values: Y = (234 N / (4.7×10^-5 m^2)) / (8.3×10^-4 m / 3.3 m) = 1.98×10^11 N/m^2.

A 33-M Long Wire with a Cross Sectional Area of 4