The peak of Mount Everest is 8840 m above sea level.Assuming that the Earth is a perfect sphere with a radius from the center to sea level of 6380 km,the gravitational acceleration at the peak of Mount Everest is

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Quizplus · Accepted Answer

The gravitational acceleration $g$ at a distance $r$ from the center of the Earth can be calculated using the formula $g = G \frac{M}{r^2}$, where $G$ is the gravitational constant, and $M$ is the mass of the Earth. As you move away from the surface of the Earth (increasing $r$), $g$ decreases. Since the radius of the Earth is 6380 km and the height of Mount Everest is 8840 m (or 8.84 km), the distance from the center of the Earth to the peak of Everest is $6380 + 8.84 = 6388.84$ km. Given that gravitational acceleration decreases with distance, and considering the relatively small increase in radius (compared to the total radius of the Earth), the decrease in $g$ would be slight, making 9.78 m/s$^2$ a reasonable approximation for the reduced gravitational acceleration at the peak.

The Peak of Mount Everest Is 8840 M Above Sea