A ball of mass 2 kg is launched into a circular orbit close to the Earth's surface.Given the mass of Earth is M = 5.98 * 10²⁴ kg and its radius is 6.37 * 10⁶ m.Ignoring air resistance,the energy required to launch the ball from rest into the orbit is

Question

Quizplus · Accepted Answer

The energy required to launch an object into a circular orbit close to the Earth's surface is given by: 
E = -G * M * m / 2 * r
where G is the gravitational constant, M is the mass of the Earth, m is the mass of the ball, and r is the radius of the Earth plus the altitude of the orbit. 
In this case, r = 6.37 * 10^6 + 10^3 = 6.38 * 10^6 m
Substituting the given values, we get: 
E = -6.67 * 10^-11 * 5.98 * 10^24 * 2 / (2 * (6.38 * 10^6))
E = -6.25 * 10^7 J 
Since energy cannot be negative, we take the absolute value of E, which gives: 
E = 6.25 * 10^7 J 
Therefore, the answer is B.

A Ball of Mass 2 Kg Is Launched into a Circular