A planet with a mass of 2.7 *10²² kg is in a circular orbit around a star with a mass of 5.3 * 10³² kg.If the planet has an orbital radius of 4.8 * 10⁹ m,what is its orbital period?

Question

Quizplus · Accepted Answer

We can use the formula for the orbital period of a planet in circular orbit around a star:
T = 2π√(r^3/GM)
where T is the period, r is the radius of the orbit, G is the gravitational constant, and M is the mass of the star. 
Plugging in the given values, we get:
T = 2π√((4.8x10^9)^3/(6.67x10^-11)(5.3x10^10))
T = 2π√(1100)
T = 6.96 hours
Therefore, the closest answer choice is C, 3.1 hours. The error could be due to rounding or significant figures in the given values.

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