A meter stick of mass 150 g is pivoted at its center.A mass m1 of 75.0 g is suspended 13.0 cm from the left end of the meter stick.How much mass m2 must be suspended 69.0 cm from the left end of the meter stick to achieve rotational equilibrium?
A) 19.4 g
B) 56.3 g
C) 98.2 g
D) 146.g
E) 38.5 g
Correct Answer:
Verified
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