A Thin Uniform Rod (Length = 75 $\theta$ With the Horizontal $\theta$

A thin uniform rod (length = 75.0 cm,mass = 1.0 kg) is pivoted about a horizontal frictionless pin through one end of the rod.The moment of inertia of the rod through this axis is (1/3) mL².The rod is released when it is below the horizontal and it makes the angle $\theta$ with the horizontal.If the angular acceleration of the rod at the instant it is released is 15.0 rad/s²,what is the angle $\theta$ ?

A) 50 ^$\circ$
B) 40 ^$\circ$
C) 20 ^$\circ$
D) 70 ^$\circ$
E) 60 ^$\circ$