A cyclist exerts a vertical force of 150 N on one end of a pedal rod of length 18 cm than is inclined at an angle 45 $\circ$ to the horizontal.The magnitude of the torque about the fixed end of the pedal rod is
A)19 Nm.
B)24 Nm.
C)27 Nm.
D)32 Nm
E)56 Nm.

Question

Quizplus · Accepted Answer

The torque is given by the formula:$$\tau = Fd\sin\theta$$where:* $\tau$ is the torque in newton-meters (Nm)* $F$ is the force in newtons (N)* $d$ is the distance from the axis of rotation to the point where the force is applied in meters (m)* $\theta$ is the angle between the force and the lever arm in degreesIn this problem, we have:* $F = 150 N$* $d = 18 cm = 0.18 m$* $\theta = 45^\circ$Plugging these values into the formula, we get:$$\tau = (150 N)(0.18 m)\sin(45^\circ) = 19 Nm$$Therefore, the magnitude of the torque about the fixed end of the pedal rod is 19 Nm.

A Cyclist Exerts a Vertical Force of 150 N on One