A massless string is wrapped around a cylinder of radius 0.100 m.A force of 100 N acts on the string.If it takes 1.2 seconds to reach an angular speed of 100 radians/s starting from rest,what is the moment of inertia of the cylinder? A)0.15 kgm² B)0.053 kgm² C)0.12 kgm² D)0.020 kgm² E)0.015 kgm²

Question

Quizplus · Accepted Answer

The moment of inertia can be calculated using the formula:

I = (T^2 * R) / (4π^2 * α)

where T is the tension in the string, R is the radius of the cylinder, and α is the angular acceleration.

In this case, T = 100 N, R = 0.1 m, α = ω/t = 100/1.2 = 83.3 radians/s^2.

Substituting these values into the formula, we get:

I = (100^2 * 0.1) / (4π^2 * 83.3) = 0.12 kgm^2

Therefore, the moment of inertia of the cylinder is 0.12 kgm^2. The correct answer is choice C.

A Massless String Is Wrapped Around a Cylinder of Radius