A stone is thrown up in the air and it reaches a maximum height of 10.0 m.What is the initial speed of the stone?

Question

Quizplus · Accepted Answer

The initial speed can be calculated using the formula for maximum height in projectile motion: $ v^2 = u^2 - 2gh $. Here, $ v = 0 $ at maximum height, $ g = 9.8 \, \text{m/s}^2 $, and $ h = 10.0 \, \text{m} $. Solving for $ u $, we get $ u = \sqrt{2gh} = \sqrt{2 \times 9.8 \times 10} = 14.0 \, \text{m/s} $.

A Stone Is Thrown Up in the Air and It